Now let’s see how much temperature change in the reactor affects the trends in conversion, selectivity and yield.
Tin(K) |
473 |
673 |
873 |
1073 |
1273 |
1473 |
1673 |
1873 |
Texit (K) |
1679 |
1839 |
1910 |
1968 |
2017 |
2063 |
2111 |
2167 |
Conversion |
0.49 |
0.60 |
0.64 |
0.66 |
0.68 |
0.70 |
0.71 |
0.72 |
Selectivity |
0.74 |
0.68 |
0.63 |
0.56 |
0.49 |
0.42 |
0.36 |
0.29 |
Yield of NO |
0.37 |
0.39 |
0.37 |
0.36 |
0.33 |
0.39 |
0.25 |
0.21 |
(Hey, what's the definition of conversion, selectivity and yield?)
Due to the exothermic nature of the reaction, the temperature will increase along the reactor. If we include this effect in our calculations, the conversion will just keep going up with increasing temperature, which means the reaction is going faster and faster. However, we do not obtain as high as conversion as before. Another interesting result is that now at T = 473 K, we still have a considerable amount of conversion. Thus, although the temperature is so low to start with, the temperature will eventually increase to 1679 K, which increases the reaction rates.
Contrast to the trend in the conversion, the selectivity decreases with increasing temperature. This is caused by the increase in temperature along the reactor makes Reaction 3 always dominant at high temperatures.
The increasing temperature along the reactor also causes the yield to decrease significantly to 0.39. The maximum yield occurs at T=673 K or T=1473 K.
Now what will happen if we also include that we have a pressure drop in the reactor? Will it change the trends in conversion, selectivity and yield? Let’s see the effect of pressure drop