Linear Difference Equations
Difference equations arise in chemical engineering from staged operations, such as distillation or extraction, as well as from differential equations modeling adsorption and chemical reactors. The value of a variable in the n-th stage is noted by a subscript n. For example, if yn,i denotes the composition of the i-th species on the n-th stage of a distillation column, xn,i is the corresponding liquid composition, R is the reflux ratio (ratio of liquid returned to the column to product removed from the condenser), and Kn,i is the equilibrium constant, then the mass balances about the top of the column give
while the equilibrium equation gives
If these are combined we get
which is a linear difference equation. This particular problem is quite complicated and the interested reader is referred to Amundson [1966, Ch. 6]. However, the form of the difference equation is clear. Several examples are given here for solving difference equations. More complete information is available in Perry [1997].
An equation in the form
can be solved by
Usually difference equations are solved analytically only for linear problems. When the coefficients are constant and the equation is linear and homogeneous a trial solution of the form
is tried; f is raised to the power n. For example, the difference equation
coupled with the trial solution would lead to the equation
This gives
where A and B are constants which must be specified by boundary conditions of some kind.
When the equation is non-homogeneous, the solution is represented by the sum of a particular solution and a general solution to the homogeneous equation.
The general solution is the one found for the homogeneous equation and the particular solution is any solution to the non-homogeneous difference equation. This can be found by methods which are analogous to those used to solve differential equations: the method of undertermined coefficients and the method of variation of parameters.
The last method applies to equations with variable coefficients, too. For a problem like
the general solution is
This can then be used in the method of variation of parameters to solve the equation