Lab 3: 2x2 Contingency table

 

For the third lab the class filled in a 2x2 contingency table according to their morning habits: coffee drinker (Y/N) and breakfast eater (Y/N).  The table and class data are given below:

 

 

Coffee

 

 

 

 

Yes

No

Total

Breakfast

Yes

22

26

48

 

No

12

3

15

 

Total

34

29

63

 

 
 

 

 

 

 

 

 

 

 

 


The class was asked to perform a test of independence on the data using Cochrane’s correction for continuity. 

 

H0: Whether someone drinks coffee is independent of whether they eat breakfast

H0: pij = pi.*p.j for i=1,…,r, j=1,…,c

 

Ha: Coffee drinking and breakfast eating are not independent

Ha: pij ≠ pi.*p.j for at least one i=1,…,r, j=1,…,c

 

df = 1*1 = 1

χ21,.05 = 3.841

 

 

The smallest expected count is:

15*29/63 = 6.905, which is greater than f=3

 

|3-6.905| = 3.905, therefore D=3.5

 

χ2c = 633*3.52/(34*29*48*15) = 4.305

 

4.305>3.841, therefore reject H0.

0.025 < P(χ21>4.305) < 0.05

 

Breakfast eating is not independent of coffee drinking.