QSCI
482 Prof. Conquest TAs
Kennedy, Malinick, Norman
HW 7--DUE FRIDAY, DECEMBER 6, 2002
1.
Scientists conducted a survey of stream segments in western
Washington to
assess the effect of three different levels of commercial
timber harvest
(none, moderate, intensive) on instream salmon spawning
habitat. One of
the responses measured on each stream segment (the
sampling unit) was the
percent of stream area comprised of pools. (Pools
are related to needed
habitat for salmon spawning.) Data and
the summary statistics are as
follows:
NONE: 43, 73, 36, 46, 42.
n = 5, xbar=48.00, s^2=208.50.
MODERATE: 39, 62, 20,
44. n = 4, xbar=41.25,
s^2=298.25
INTENSIVE: 37, 14, 21, 30, 07. n = 5, xbar=21.80,
s^2=144.7.
1a. At the .05 level of significance [and assuming
normality and equal
variances], test to see whether the three levels of
timber harvest yield
the same mean pool fraction of stream area. Include
the complete analysis
of variance (ANOVA) table. You may do this either by
hand (it is indeed
do-able by hand) or by using statistical software like
SPSS. NOTE: in
writing up your "conclusions" statement, AVOID the words
"accept",
"reject", and "hypothesis";
rather, express conclusions in terms of the
original research
question.
1b. Are the three levels of timber harvest a "fixed
effects" model or a
"random effects" model? Explain your
answer.
1c. If we were to
use a sample size of n=6 for each group (total sample
size = 18), how far
apart would the largest and smallest population
means have to be in order
to reject the null hypothesis with 90% power
and level of significance =
.05?
1d. Now, at the alpha =
5 percent level of significance, do a parametric
(normality based)
multiple comparison of means using the Student-Newman
Keuls method of
multiple comparisons.
2. A
study comparing the effects of different toxic substances upon
aquatic
communities yields the following results [response variable is:
a
"toxicity index"--the higher the index, the worse the
contamination].
CONTROLS: 105.0, 103.5, 84.2, 93.6, 113.6, 68.5,
124.7, 68.8
PCBs: 134.6, 140.1, 118.5, 122.3, 120.5
CADMIUM: 111.4,
112.0, 90.7, 103.9, 98.6,
MERCURY: 107.8, 132.0, 105.1, 149.0,
106.9
DESCRIPTIVE STATS:
CONTROLS: xbar = 95.24; std. dev. = 20.38
PCBs: xbar = 127.20; std. dev. = 9.56
CADMIUM: xbar = 103.32; std. dev. = 8.98
MERCURY: xbar = 120.16; std. dev. = 19.54
pooled
MSE = 269.62; pooled std. dev. = 16.42
Using analysis of variance,
we have been able to reject the null
hypothesis of equality of the 4
treatment means. For multiple comparison
purposes, we are really only
interested in whether or not each of the 3
non-control groups [PCBs,
Cadmium, Mercury] differ from the control in
terms of the mean. At the .05 level of significance, carry out
the
appropriate test to see if each of the PCB mean, Cadmium mean,
Mercury
mean differs from the control mean. Summarize your
conclusions.
3. The following data are from an experiment to look
at
weight gain [in gms] of lab mice under 3 different diets which have
low, medium, and high amounts of protein and other nutrients. It was
also felt that male mice might
respond to the diets differently than
female mice, so sex of the animal
was also noted.
FEMALES MALES
LOW 40.8 49.2
40.5 43.8
43.9 37.6
MED 51.5 50.9
50.0 57.9
51.9 59.9
HIGH 62.7 74.0
56.4 72.1
64.7 73.9
MEAN
The
Sums of Squares for the different sources of variation for the
above data
are as follows:
SOURCE OF
VARIATION SS
Diet 1831.9
Sex
179.9
Diet
x Sex Interaction 82.4
Error 161.0
---------------------- -----
TOTAL 2255.2
a.
At the .10 level of significance, test for the presence of interaction
between
Diet and Sex. Why did the result of the
test turn out the way it
did? Use a PLOT of the means [plot can be done by
hand] to explain why.
b. At the .05 level of significance, test for
the overall effect of Sex on
the mean weight gain. Why did the result of the test turn out the
way it
did?--refer to your plot from [a] to answer this.
c. At
the .05 level of significane, test for the overall effect of the
three
Diets on the mean weight gain. Why did
the result of the test turn
out the way it did?--refer to your plot from
[a] to answer this.